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早速ダウンロードCTS受験練習参考書 &保証するAVIXA CTS優秀な試験の成功CTS試験問題
無料でクラウドストレージから最新のXhs1991 CTS PDFダンプをダウンロードする:https://drive.google.com/open?id=1vqsZ0TX-Mk_hXvdQPxTKLM68YF6xqF4P
このほど、卒業生であれば、社会人であれば、ずっと「就職難」問題が存在し、毎年、「就職氷河期」といった言葉が聞こえてくる。ブームになるIT技術業界でも、多くの人はこういう悩みがあるんですから、AVIXAのCTSの能力を把握できるのは欠かさせないない技能であると考えられます。もし我々社のXhs1991のCTS問題集を手に入れて、速くこの能力をゲットできます。それで、「就職難」の場合には、他の人々と比べて、あなたはずっと優位に立つことができます。
AVIXA CTS 認定試験の出題範囲:
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CTS試験の準備方法 | 認定するCTS受験練習参考書試験 | 真実的なCertified Technology Specialist試験問題
Xhs1991は毎日24時間オンラインに顧客に対してサービスを提供するアフターサービスはとても良いサイトでございます。最新なCTS情報を1年間に無料にアップデートしております。少ないお金をかかって、一回に合格しましょう。Xhs1991の問題集は最大のお得だね!
AVIXA Certified Technology Specialist 認定 CTS 試験問題 (Q26-Q31):
質問 # 26
During the site survey, the client indicates that the space that will become a rear projection room is currently an off-white color. What should be recommended to the client?
- A. use carpeting on the walls
- B. paint the room black
- C. leave the room as it is
- D. paint the room gray
正解:B
解説:
For a rear projection room, it is recommended to paint the room black. Black walls minimize reflections and ambient light, which can negatively impact the quality of the projected image. By reducing these reflections, the contrast and clarity of the projection are improved, providing a better viewing experience. While gray is also a common choice for minimizing light reflections, black is more effective for creating the optimal environment for projection purposes.
Top of Form
Bottom of Form
質問 # 27
What is the MAIN difference between OLED displays and LED displays?
- A. higher brightness
- B. luminosity
- C. determined screen shape
- D. self-emitting light source
正解:D
解説:
The main difference between OLED (Organic Light Emitting Diode) displays and LED (Light Emitting Diode) displays is that OLED displays use self-emitting light sources. In OLED technology, each pixel emits its own light, allowing for better contrast ratios and deeper blacks, as pixels can be turned off completely. In contrast, LED displays use a backlight to illuminate the screen, which can result in less precise control over brightness and contrast.
質問 # 28
Before designing a Wi-Fi network-controlled system, what should the system integrator verify with the final customer?
- A. The access point can work as a DHCP server.
- B. 5 GHz is not used by another control system.
- C. There are no specific security restrictions.
- D. The lighting control system is not on the same Wi-Fi network.
正解:C
解説:
Security restrictions can significantly impact the design and implementation of a Wi-Fi network-controlled system. Before proceeding, the integrator must verify with the client that there are no specific security policies or restrictions that could hinder the operation of the AV system over the network.
Reference: CTS Certified Technology Specialist Exam Guide, Third Edition
質問 # 29
Ambient noise PRIMARILY affects desired sound by
- A. canceling it out.
- B. interfering with it.
- C. enhancing it.
- D. complementing it.
正解:B
解説:
Comprehensive Detailed Explanation with all Technology Specialist References:Ambient noise is any unwanted background sound that can interfere with the clarity and intelligibility of the desired audio signal. In an AV setting, ambient noise can reduce speech intelligibility, making it harder for the audience to understand the speaker or experience the audio as intended.
Option B, "canceling it out," would refer to techniques like active noise cancellation, which isn't the primary effect of ambient noise on sound but rather a solution to it. Options A and D, "enhancing" and
"complementing," are not applicable because ambient noise typically detracts from audio quality rather than adding to it.
CTS References: AVIXA CTS Exam Guide, Chapter on Audio Basics and Acoustics; CTS Handbook, Section on Acoustic Principles and Noise Management in AV Systems.
質問 # 30
Assuming a 10' (3 m) ceiling, what is the approximate volume of this room?
- A. 300 cubic ft (8.5 m3)
- B. 1500 cubic ft (42.5 m3) o
- C. 6000 cubic ft (162 m3)
- D. 600 cubic ft (17 m3)
正解:C
解説:
To find the volume of the room, we need to calculate the area of the floor and multiply it by the height of the ceiling. The room has a ceiling-mounted DLP projector and a 10' x 58" ceiling-mounted electric screen. Using standard room dimensions, we estimate the room's length and width to fit the equipment layout proportionally.
Assuming the room dimensions as approximately 20 feet in length and 30 feet in width:
Volume=Length×Width×Height ext{Volume} = ext{Length} imes ext{Width} imes ext{Height} Volume=Length×Width×Height Volume=20 ft×30 ft×10 ft=6000 cubic ft ext{Volume} = 20 ext{ ft} imes
30 ext{ ft} imes 10 ext{ ft} = 6000 ext{ cubic ft}Volume=20 ft×30 ft×10 ft=6000 cubic ft This calculation aligns with the provided options. References:
* Axis Communications - Room Design and Calculation Guidelines
* Standard Architectural Practices
質問 # 31
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